RSA {3} 给n,e,dp,c

dP

dPd(modp1)dP \equiv d \pmod{p-1}

dP×ed×e1(modp1)\because dP \times e \equiv d \times e \equiv 1 \pmod {p - 1}
dP×e1k×(p1)\therefore dP \times e - 1 \equiv k \times (p - 1)
(dP×e1)×d×ek×(p1),kk×d×e\therefore (dP \times e - 1) \times d \times e \equiv k' \times (p - 1), k' \equiv k \times d \times e
\Leftrightarrow